2x^2-3x+2=x^2-3x-5

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Solution for 2x^2-3x+2=x^2-3x-5 equation: 



2x^2-3x+2=x^2-3x-5

We move all terms to the left:

2x^2-3x+2-(x^2-3x-5)=0

We get rid of parentheses

2x^2-x^2-3x+3x+5+2=0

We add all the numbers together, and all the variables

x^2+7=0

a = 1; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·1·7
Δ = -28
Delta is less than zero, so there is no solution for the equation

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